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-3-3x^2=5x^2+15
We move all terms to the left:
-3-3x^2-(5x^2+15)=0
We get rid of parentheses
-3x^2-5x^2-15-3=0
We add all the numbers together, and all the variables
-8x^2-18=0
a = -8; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·(-8)·(-18)
Δ = -576
Delta is less than zero, so there is no solution for the equation
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